3936=16t^2

Solution for 3936=16t^2 equation:

3936=16t^2

We move all terms to the left:

3936-(16t^2)=0

a = -16; b = 0; c = +3936;
Δ = b2-4ac
Δ = 02-4·(-16)·3936
Δ = 251904
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{251904}=\sqrt{1024*246}=\sqrt{1024}*\sqrt{246}=32\sqrt{246}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32\sqrt{246}}{2*-16}=\frac{0-32\sqrt{246}}{-32}
=-\frac{32\sqrt{246}}{-32}
=-\frac{\sqrt{246}}{-1}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32\sqrt{246}}{2*-16}=\frac{0+32\sqrt{246}}{-32}
=\frac{32\sqrt{246}}{-32}
=\frac{\sqrt{246}}{-1}
$